Answer:
mass of other block is 0.7142 kg
Explanation:
given data
mass = 5.0 kg
accelerates downward = [tex]\frac{3}{4} g[/tex]
to find out
mass of other block
solution
we will apply here Newton 2nd law that is
force ∑Fy = mass × acceleration
so
t - mg = ma .............1
t = 5 ( 9.8 + [tex](\frac{-3}{4} 9.8)[/tex] )
t = 12.25 N
so other block mass is from equation 1
t - mg = ma
t = m ( g+a)
12.25 = m ( g + [tex](\frac{3}{4} 9.8)[/tex] )
12.25 = m ( [tex]\frac{7}{4}[/tex] 9.8
m = 0.7142 kg
mass of other block is 0.7142 kg
The mass of the other block moving upwards is 4.71 kg.
The given parameters;
The tension on the pulley due to the block moving downwards is calculated as follows;
T = W - ma
T = mg - ma
T = m(g - a)
T = 5(9.8 - 34 x 9.8)
T = -1617 N
The mass of the block that will be moving upwards is calculated as;
T = ma + mg
T = m( a + g)
1617 = m(34 x 9.8 + 9.8)
1617 = 343m
[tex]m = \frac{1617}{343} \\\\m = 4.71 \ kg[/tex]
Thus, the mass of the other block moving upwards is 4.71 kg.
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