Answer with Step-by-step explanation:
We are given that a ball is thrown into the air with velocity
[tex]v=40ft/s[/tex]
Height after t seconds is given by
[tex]s(t)=40t-16t^2[/tex]
We have to find the average velocity for the ball during the time [1,2].
We know that average velocity=[tex]\frac{ds}{dt}[/tex]
Average velocity=v=[tex]\frac{d(40t-16t^2)}{dt}=40-32t[/tex]
Substitute t=1 then we get
Average velocity=[tex]40-32(1)=40-32=8 m/s[/tex]
Substitute t=2 then
Average velocity=[tex]40-32(2)=40-64[/tex]
Average velocity[/tex]=-24 m/s[/tex]
