Answer:
The dimensions of the rectangle is [tex]58\times 12[/tex] units.
Step-by-step explanation:
Given : The perimeter of a rectangle is 140 and the length is 10 more than four times the width.
To find : The dimensions ?
Solution :
Let the width of the rectangle is W=x
The length is 10 more than four times the width.
i.e. the length of the rectangle is L=4x+10
The perimeter of the rectangle is
[tex]P=2(L+B)[/tex]
[tex]140=2(4x+10+x)[/tex]
[tex]70=5x+10[/tex]
[tex]5x=60[/tex]
[tex]x=\frac{60}{5}[/tex]
[tex]x=12[/tex]
The width is 12 unit.
The length is 4(12)+10=48+10=58 unit.
Therefore, the dimensions of the rectangle is [tex]58\times 12[/tex] units.
