Answer:
The values are a=1 b=10 c=25 and solving the expression we get x=-5
Explanation:
Given equation; [tex]x^{2}+10 x+25[/tex]
Solution:
The above equation can be written as [tex]x^{2}+10 x+25=0[/tex]
This equation is in the form of [tex]A x^{2}+B x+C=0[/tex]
[tex]A x^{2}+B x+C=0[/tex] is the general quadratic equation.
Comparing the above equation we get
A=1, B=10 and C=25
To find value of “x” we use the formula as
=[tex]\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}[/tex]
Substitute the values of a, b and c in the above equation we get
=[tex]\frac{-(10) \pm \sqrt{10^{2}-4(1)(25)}}{2(1)}[/tex]
=[tex]\frac{-(10) \pm \sqrt{100-4(1)(25)}}{2}[/tex]
=[tex]\frac{-(10) \pm \sqrt{100-100}}{2}[/tex]
=[tex]\frac{-10}{2}[/tex]
=-5
Results:
Thus the values are A=1, B=10, C=25 and X=-5
