Answer
angle made by the horizontal = 30°
velocity = 5 m/s
distance = 7 m
Vertical component (V y) = 5 sin (30°) = 2.5 m/s
Horizontal component(V x) = 5 cos (30° ) = 4.33 m/s
Applying
[tex]s = u t +\dfrac{1}{2}gt^2[/tex]
[tex]7 = 2.5 t +0.5\times9.8 t^2[/tex]
t = 0.967 s
b) Distance from base
= [tex]V_x \times t[/tex]
= [tex]2.5\times 0.967[/tex]
= 2.42 m
c) You can find final vertical velocity
V= u + gt
V = 9.8 × 0.967
v = 9.48 m/s
Final velocity =[tex]\sqrt{(9.48^2 - 4.33^2)}[/tex]
v = 8.433 m/s
Final angle
[tex]\theta = tan{-1}\dfrac{v_y}{v_x}[/tex]
[tex]\theta = tan{-1}\dfrac{9.48}{4.33}[/tex]
θ = 65.41°
