Answer:
Distance, d = 526.85 meters
Explanation:
It is given that,
Speed of the car, u = 30 m/s
As it comes down, v = 0
It is travelling up a 5 degrees slope. Let d is the distance it coast before starting to roll back down. Let d is the distance. It is calculated as :
[tex]d=\dfrac{v^2-u^2}{2a}[/tex]
a is the acceleration. For an inclined plane, [tex]a=g\ sin\theta[/tex]
[tex]d=\dfrac{v^2-u^2}{2g\ sin\theta}[/tex]
Putting all the values in above formula as :
[tex]d=\dfrac{-(30)^2}{2\times 9.8\times \ sin(5)}[/tex]
d = -526.85 meters
So, it will coast 526.85 meters before starting to roll back down. Hence, this is the required solution.
