Answer:
[tex]\large \boxed{\text{h. 20 000 N}}[/tex]
Explanation:
Force is the change in momentum over time
F = Δp/Δt
1. Calculate the change in momentum
p₁ = mv₁ = 1000 kg × 10 m/s = 10 000 kg·m·s⁻¹
p₂ = 0
Δp = p₂ - p₁= (0 - 10 000) kg·m·s⁻¹ = -10 000 kg·m·s⁻¹
2. Calculate the force
[tex]\begin{array}{rcl}F & = & \dfrac{\Delta p}{\Delta t}\\\\& = & \dfrac{-10 000 \text{ kg$\cdot$m$\cdot$ s}^{-1}}{\text{ 0.5 s}}\\\\& = & \textbf{-20 000 N}\\\end{array}\\\text{The negative sign shows that the force is exerted opposite to the direction of motion.}\\\text{The magnitude of the force is $\large \boxed{\textbf{20 000 N}}$}[/tex]
The magnitude of the force exerted on the truck during the collision is 20,000N
The magnitude of the force exerted on the truck during the collision is expressed according to Newton's second law;
[tex]F = ma\\F=m(\frac{v-u}{t} )\\[/tex]
m is the mass of the object = 1000kg
v is the final velocity = 10m/s
u is the initial velocity = 0m/s
t is the time taken = 0.5secs
Substitute the given parameters into the formula:
[tex]F=1000(\frac{10-0}{0.5} )\\F=1000(\frac{10}{0.5})\\F=1000\times 20\\F=20,000N[/tex]
Hence the magnitude of the force exerted on the truck during the collision is 20,000N.
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