Answer:
[tex]0.188 m/s^2[/tex]
Explanation:
Assuming the crate does not lift above the ground and remains along the floor, then its acceleration will be in the horizontal direction. Therefore, we can use Newton's second law to find its acceleration:
[tex]F_x = ma_x[/tex]
where
[tex]F_x[/tex] is the net force on the crate along the x-direction
m is the mass of the crate
[tex]a_x[/tex] is the acceleration
Here we have:
m = 50.0 kg
[tex]F_x = F cos \theta = (10.0 N)(cos 20.0^{\circ})=9.4 N[/tex] is the component of the pulling force along the horizontal direction
Solving for the acceleration,
[tex]a_x = \frac{F_x}{m}=\frac{9.4}{50.0}=0.188 m/s^2[/tex]
