Answer:
[tex]3x_0[/tex]
Explanation:
The horizontal distance covered by the ball in the falling is only determined by its horizontal motion - in fact, it is given by
[tex]d=v_x t[/tex]
where
[tex]v_x[/tex] is the horizontal velocity
t is the time of flight
The time of flight, instead, is only determined by the vertical motion of the ball: however, in this problem the vertical velocity is not changed (it is zero in both cases), so the time of flight remains the same.
In the first situation, the horizontal distance covered is
[tex]d=v_0 t = x_0[/tex]
in the second case, the horizontal velocity is increased to
[tex]v_x' = 3v_0[/tex]
And so the new distance travelled will be
[tex]d' = v_x' t = 3 v_0 t = 3 x_0[/tex]
So, the distance increases linearly with the horizontal velocity.
The ball will land at a distance from the table three times greater than the initial distance.
Velocity can be defined as the change in the position of the object in a particular direction.
The horizontal component of velocity,
[tex]d = v_x t[/tex]
Where,
[tex]d[/tex] - distance
[tex]v_x[/tex] - horizontal velocity
[tex]t[/tex] - time of flight
The time of flight can be calculated by the verticle velocity,
[tex]d = v_y t [/tex]
Since the Velocity is [tex] v_0[/tex]
[tex]d = 3v_0\\ d = x_0[/tex]
When the ball rolled off from the desk, then velocity,
the horizontal distance,
[tex]d' = v'xt\\ d' = 3v_0 t\\ d' = 3x_0[/tex]
Therefore, the ball will land at a distance from the table three times greater than the initial distance.
Learn more about velocity:
https://brainly.com/question/13510190
