Respuesta :
Answer:
a)It is shown in the figure
b)Continuos... transient state... steady-state
c)molar flow rate of the liquid is 28 14 mol/min of bencene (28%) and 36 mol/min of toluene (72%)
Composition of vapor is 0.388 and 0.612 for B and T, respectively
Explanation:
a)In the beginning, the vapor Flow rate is 0% which means that the liquid Flow rate is 100%. The figure attached shows how at time=0, liquid=100 and vapor=0. With time, the Flow rate of vapor and liquid approach to 50% of the molar flow rate of the feed stream. The figure shows the plot of Vapor/liquid Flow rates versus time.
b)The problem mentions that the feed stream is fed at a constant rate to the reactor, thus the process is continuous. As is shown in the figure, before the Flow rate reaches the asymptotic limit, the flowrate is changing and it is time-dependent, which means before the asymptotic limit, the process is in transient state. Then, after the asymptotic limit, the vapor/liquid flowrates are constants which means the process is in steady-state.
c)The Flow diagram process is shown in the figure where Benzene is represented as B and toluene as T.
Feed flow rate:
In the feed Flow rate, B and T are given, the molar fraction for B is 0.446 and the one for T is 55.4
B balance
we make a balance for B, we can calculate the molar Flow rate in vapor stream, the balance for B is:
A*Xba= CXbc + DXbd wher A, C and D are the feed, vapor and liquid streams, respectively, and Xba, Xbc and Xbd are the molar fractions of bencene in the corresponding stream.
A=100 mol/min, Xba=0.446, C=50 mol/min, Xbc=?, D=50 mol/min, Xbd= 0.28.
If you solve for Xbc, yo get the molar fraction of bencene in vapor stream is 0.388 and the toluene fraction is 0.612
