Answer:
a=250.62m/s^2
x=320.8m
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X (2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 4 above equations and use algebra to solve
for this case we use the ecuation number 1
Vf=401m/S
Vo=0m/s
t=1.6s
[tex]Vf=Vo+a.t\\a=\frac{Vf-Vo}{t} \\\\a=\frac{401-0}{1.6} =250.62m/s^2[/tex]
for the second part we use the ecuation number 2
[tex]\frac{ {Vf^{2}-Vo^2}}{2a} =X\\\frac{ {401^{2}-0^2}}{2(250.625)} =320.8m\\[/tex]
