Answer:
≈ 1.7346s
Explanation:
Because we are trying to find when it is at it's highest point we can safely say that it's velocity at that point is 0m/s,
therefore we can use the equation:
[tex]v_f = a(t_t) + v_i[/tex]
and do some algebra to get:
[tex]\frac{v_f - v_i}{a} = t_t[/tex]
Now we plug in our values (note that this is assumed to be on Earth and that because it says that upwards is positive, we set g to be negative to say that it is pointing down):
[tex]\frac{0m/s - 17m/s}{-g} = t_t[/tex]
=
[tex]\frac{-17m/s}{-9.8m/s^2} = t_t[/tex]
=
[tex]\frac{17}{9.8s} = t_t[/tex]
≈
[tex]1.7346s \approx t_t[/tex]
