Answer:
Speed before applying brakes = 64.8
Step-by-step explanation:
The formula is given as:
[tex]s=\sqrt{24d}[/tex]
Where
s is speed of car, and
d is length of skid marks
It is given that d = 175 ft, so we substitute and find the speed of the car before the brakes were applied.
[tex]s=\sqrt{24d}\\s=\sqrt{24*175}\\s=64.81[/tex]
Rounding to nearest tenth, that is 64.8
Answer:
The vehicles must travel at a speed of 64.8 ft/s before he applied brakes as we know the length of skid marked was 175 feet.
Explanation:
For the given values in the above question we came to know that the vehicle skidded till 175 feet and the investigator wants to know in how much speed the vehicle is travelling.
As given in question, [tex]S=\sqrt{24 d}[/tex]
Where, S is speed of the vehicle , d is distance the vehicle skidded
Now, [tex]S=\sqrt{24 \times 175}=\sqrt{4200}=64.8[/tex]
∴ Speed of the vehicle before applying breaks is 64.8 ft/s .
