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A stock person at the local grocery store has a job consisting of the following five segments: (1) picking up boxes of tomatoes from the stockroom floor (2) accelerating to a comfortable speed (3) carrying the boxes to the tomato display at constant speed (4) decelerating to a stop (5) lowering the boxes slowly to the floor. During which of the five segments of the job does the stock person do positive work on the boxes?

Respuesta :

Answer:

option 1 and option 2

Explanation:

option 1 and option 2

1)Take up the box: force is upwards, displacement is upwards as well, so good work as force & displacement are in the same direction

2) Accelerating:: because the individual is moving, force is positive, displacement is also in the same direction, so the work is positive.

3) carrying box at fixed speed :: as speed remain constant , force = 0 , therefore work =0

4) Decelerating to stop :: force is -ve because it is moving to finally stop, thus negative work

5) Lowering of the box :: force acts up direction , displacement is down , hence -ve work

Parrain

The segments where the stock person does positive work are:

  • Picking up boxes of tomatoes from the stockroom floor.
  • Accelerating to a comfortable speed.

Why are these considered positive work?

Positive work refers to when the force being applied and the displacement of items are in the same direction.

When picking up boxes from the ground and accelerating at a comfortable speed, positive work is occurring because the force and the displacement are considered to be going in the same direction.

In conclusion, options 1 and 2 are correct.

Find out more on positive work at https://brainly.com/question/1472151.

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