Answer:
Expression:
[tex] \frac{x}{ - 1} + 11 \leqslant 15[/tex]
Solution set:
[tex]x \geqslant - 4[/tex]
Step-by-step explanation:
Let the number be x
The quotient of a number and negative one and a number then becomes
[tex] \frac{x}{ - 1} [/tex]
Now this quotient is increased by 11, so we write:
[tex] \frac{x}{ - 1} + 11[/tex]
This expression is now less than or equal to 15.
[tex] \frac{x}{ - 1} + 11 \leqslant 15[/tex]
We can solve this for x.
[tex] - x + 11 \leqslant 15[/tex]
[tex] \implies \: - x \leqslant 15 - 11[/tex]
[tex] \implies \: - x \leqslant 4[/tex]
Divide through by -1 and reverse the inequality sign
[tex]\implies \: x \geqslant - 4[/tex]
