Answer:
0.45 or 45%
Explanation:
For the first integer:
propability=[tex]\frac{1}{10} = 0.1[/tex]
For the second number (strictly greater), we consider every case possible
if the first integer is:
10, then 0 numbers would satisfy the criteria
9, then 1 number would satisfy the criteria
8, then 2 numbers would satisfy the criteria
7, then 3 numbers would satisfy the criteria
6, then 4 numbers would satisfy the criteria
5, then 5 numbers would satisfy the criteria
4, then 6 numbers would satisfy the criteria
3, then 7 numbers would satisfy the criteria
2, then 8 numbers would satisfy the criteria
1, then 9 numbers would satisfy the criteria
So, the probability for each case si calculated dividing the numbers that would satisfy the criteria by the total:
10, (0/10) we consider it 0
9, (1/10) = 0.1
8, (2/10) = 0.2
7, (3/10) = 0.3
6, (4/10) = 0.4
5, (5/10) = 0.5
4, (6/10) = 0.6
3, (7/10) = 0.7
2, (8/10) = 0.8
1, (9/10) = 0.9
finally, add all the probabilities for all possible cases, and divide it by the number of cases (10)
[tex]\frac{4.5}{10} =0.45[/tex]
