Answer:
COP=Refrigeration Cycle=4.67
COP=heat pump=5.67
Explanation:
Hello!
To solve this problem we must consider the following
There are three related energy flows for these types of problems:
Qh = heat rejected,
Wcycle = the electrical power entering the compressor.
Qo = heat entering
if we apply the principle of conservation of energy we can find Qo
Qo+Wcycle=Qh
Qo=Qh-Wcycle
Qo=Qh-Wcycle
Qo=1700-300=1400BTU
We now remember that for a refrigerator the operational coefficient COP is the ratio between the heat entering the Qo system, and the power supplied.
[tex]COP=\frac{Qo}{Wcycle} =\frac{1400}{300} =4.67[/tex]
We now remember that for a heat pump the operational coefficient COP is the ratio between the heat that rejected Qh, and the power supplied.
[tex]COP=\frac{Qh}{Wcycle} =\frac{1700}{300} =5.67[/tex]
