Respuesta :
Answer:
[tex]y=3x-50[/tex]
Step-by-step explanation:
You are given the table
[tex]\begin{array}{cc}\text{Tickets Sold}&\text{Profit}\\ \\50&100\\100&250\\150&400\\200&550\end{array}[/tex]
The linear equation of the line passing through the points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Choose two points, for example, [tex](50,100)[/tex] and [tex](100,250)[/tex] and use the equation above:
[tex]y-100=\dfrac{250-100}{100-50}(x-50)\\ \\y-100=\dfrac{150}{50}(x-50)\\ \\y-100=3(x-50)\\ \\y-100=3x-150\\ \\y=3x-50[/tex]
Check two remaining points:
[tex](150,400): \ \ 3\cdot 150-50=450-50=400\\ \\(200,550):\ \ 3\cdot 200-50=600-50=550[/tex]
Answer:
the slope of the line through these points is 3
Step-by-step explanation:
Given that:
#Tickets #Sold Profit (dollars)
50 100
100 250
150 400
200 550
Find the slope of the line through these points
As we know, the slope of a linear line can be calculated as following:
m = Δy / Δx , where:
- Δy = y2 - y1
- Δx = x2 -x1
In this situation,
- let the point (50 100) is (x1, y1),
- let the point (100, 250) is (x2, y2),
We have the slope:
m = (250 -100) / (100 -50) = 150 / 50 = 3
So the slope of the line through these points is 3