Answer:
The mass of the air is 0.0243 kg.
Explanation:
Step1
Given:
Stroke of the cylinder is 320 mm.
Bore of the cylinder is 280 mm.
Pressure of the air is 101.3 kpa.
Temperature of the air is 13°C.
Step2
Calculation:
Stroke volume of the cylinder is calculated as follows:
[tex]V=\frac{\pi }{4}d^{2}L[/tex]
[tex]V=\frac{\pi}{4}\times(\frac{280}{1000})^{2}\times(\frac{320}{1000})[/tex]
V = 0.0197 m³.
Step3
Assume air an ideal gas with gas constant 287 j/kgK. Then apply ideal gas equation for mass of the air as follows:
PV=mRT
[tex]m=\frac{PV}{RT}[/tex]
[tex]m=\frac{101.3\times 1000\times 0.0197}{287\times (13+273)}[/tex]
m= 0.0243 kg.
Thus, the mass of the air is 0.0243 kg.
