Answer:
A) 1384.6 J/g
b)110.768 MJ
Explanation:
Given data:
[tex]T_{melting} = 1668 degree C[/tex]
density of titanium = 4.5 g/cm^3
specific heat = 0.544 J/g degree C
heat of fusion = 419 J/g
Pouring temperature for titanium = 1800 degree C
Initial temperature = 25 degree C
a) eneegy for heating unit mass is given as
[tex]E = C(T_{melting} - T_{initial}) + L + C(T_{pouring} - T_{melting})[/tex]
[tex]= 0.544(1668-25) + 419 + 0.544(1800-1668)[/tex]
= 1384.6 J/g
b) Total energy to heat 80 kg metal
we know for one unit 1384.6 J/g energy is required
therefore for 80 kg , energy required is
[tex]E = (80\times 1000) 1384.6[/tex]
= 110768000 J
[tex]= 110.768 \times 10^6 J[/tex]