Answer:
Step-by-step explanation:
Slope of a line 2x+3y=6 is -2/3
So line passing through (0,4) has same slope because both are parallel
From slope intercept form we have
Y-y1 =m(x-1)
Y-4= -2/3(x-0)
3Y-12 = -2x
3Y+2x = 12
Which is required equation of a line.
The equation of a line parallel to the line 2x + 3y = 12 and passing through the point (0,4) is;
2x + 3y = 12.
To write the equation for a line parallel to the line 2x + 3y = 6; we must first determine the slope of the line.
By rewriting the equation 2x + 3y = 6 to resemble the standard slope-intercept form; we have;
y = (-2/3)x + 2.
Therefore, the slope, m1 of line 2x + 3y = 6 is;
However, since the lines are parallel,
Therefore, the equation of the parallel line which passes through the point (0,4) is given as;
By cross product;
2x + 3y = 12
Therefore, the equation of a line parallel to the line 2x + 3y = 12 and passing through the point (0,4) is; 2x + 3y = 12.
Read more:
https://brainly.com/question/13937518
