Answer:
The price of one Wii game is $50
Step-by-step explanation:
Let the cost of 1 Nintendo DS games be x
Cost of 2 Nintendo DS games = 2x
Cost of 3 Nintendo DS games = 3x
Let the cost of 1 Wii game be y
Cost of 4 Wii game = 4y
Cost of 2 Wii game = 2y
Now we are given that Emily went to a toy store that was selling two Nintendo DS games and four Wii games for a total of $240
So, [tex]2x+4y = 240[/tex] --- A
Emily bought three DS games and two Wii games and spent $160
So, [tex]3x+2y = 160[/tex] ---- B
Plot lines A and B on graph . Intersection point will provide the solution .
[tex]2x+4y = 240[/tex] -- Green
[tex]3x+2y = 160[/tex] -- Blue
Intersection Point = (20,50)
So, Cost of 1 Nintendo DS games = $20
Cost of 1 Wii game = $50
Hence the price of one Wii game is $50
The price of one WII game is $50.
2n + 4w = 240 equation 1
3n + 2w = 160 equation 2
Where:
n = price of nintendo games
w = price of wii game
In order to determine the required game, multiply equation 1 by 2 and equation 2 by 3
6n + 12w = 720 equation 3
6n + 4w = 320 equation 4
Subtract equation 4 from 3
8w = 400
w = 50
