ITELAND
contestada

Point J is on line segment IK. Given JK = 2x – 1, IK = 3x + 2,
and I J = 3x – 5, determine the numerical length of JK.

Respuesta :

Answer:

JK=7

Step-by-step explanation:

From the line segment, since J is on it ,it means the line segment is

represented as I J K

from this illustration, we can say that the longest part of the line segment is from I to K

this means that, IJ +JK =IK

making JK the subject,

JK= IK - IJ

but from the question, JK=2x-1 , IK=3x+2 and IJ=3x-5

substituting them in the expression,

2x-1 =3x+2 -(3x-5)

solving for x

2x-1 =3x+2-3x+5

2x-1 =0+7

2x-1 =7

2x=1+7

2x=8

dividing through by 2

2x/2 =8/2

x=4

but the question says we should find the numerical value for JK

but from the line segment,

JK=2x-1

but now we know the value of x to be 2

so substituting it in the formula

JK= 2(4)-1

JK=8-1

JK=7

therefore, the numerical value for JK is 7