Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle, or a parallelogram. Then find the perimeter of the quadrilateral. A(6, –4), B(11, –4), C(11, 6), D(6, 6)

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Answer:

The answer to your question is: it's a rectangle

perimeter = 30 u

Step-by-step explanation:

d = √((x2.x1)² + (y2-y1)²)

Now, calculate the distances AB, BC, CD, AD

dAB = √((11-6)² + (-4+4)² = √5² = 5

dBC = √((11-11)² + (-4-6)² =√10 = 10

dCD = √((6-11)² + (6-6)² = √5² = 5

dAD = √((6-6)² + (6+4)² = √10² = 10

From the results we conclude that is a rectangle because two sides have the same length and the other two also measure the same. We can draw it to confirm this.

Perimeter = dAB + dBC + dCD + dAD

                 = 5 + 10+ 5 + 10 = 30 units