Answer:32.24 s
Explanation:
Given
mass of runner (m)=51.8 kg
Constant acceleration(a)=[tex]1.31 m/s^2[/tex]
Final velocity (v)=5.47 m/s
Time taken taken to reach 5.47 m/s
v=u+at
[tex]5.47=0+1.31\times t[/tex]
[tex]t=\frac{5.47}{1.31}=4.17 s[/tex]
Distance traveled during this time is
[tex]s=ut+\frac{1}{2}at^2[/tex]
[tex]s=\frac{1}{2}\times 1.31\times 4.17^2=11.42 m[/tex]
So remaining distance left to travel with constant velocity=153.57 m
thus time [tex]=\frac{distance}{speed}[/tex]
[tex]t_2=\frac{153.57}{5.47}=28.07 s[/tex]
Total time=28.07+4.17=32.24 s
