Answer:
6298702 potassium atoms would have to be laid side by side to span a distance of 2,91 mm
Explanation:
If the radius of a potassium atom is 231 pm, then the diameter would be:
d = 2r = 2*(231) = 462 pm
So each potassium atom occupies a space of 462 pm, we can express this relationship as follows:
[tex]\frac{1 potassium atom}{462 pm}[/tex]
To solve this problem, we'll use the following conversion factors:
1 pm = 1×E−12 m
1000 mm = 1 m
We begin to accommodate all our relationships starting from that numerical expression that is not written as a relationship (usually the one in the question), and in such a way that the units are eliminated between them.
[tex]2, 91 mm * \frac{1 m}{1000 mm}*\frac{ 1 pm}{1*10^{-12}m }*\frac{1 potassium atom}{462 pm}= 6298701.3[/tex] potassium atoms
So, we'll need 6298702 potassium atoms to span a distance of 2,91 mm
