Respuesta :
Answer:
So the car displacement after 3.7 sec is 0.030 km
Explanation:
We have given initial velocity u = 6.64 m/sec
Acceleration [tex]a=0.85m/sec^2[/tex]
Time t = 3.7 sec
Final velocity v = 9.8 m/sec
We have to find the displacement after that time
From second equation of motion we know that [tex]s=ut+\frac{1}{2}at^2[/tex], here s is displacement, u is initial velocity, t is time , and a is acceleration
So displacement [tex]s=ut+\frac{1}{2}at^2=6.64\times 3.7+\frac{1}{2}\times 0.85\times 3.7^2=30.386m[/tex]
We know that 1 km = 1000 m
So 30.386 m = 0.030 km
Answer:
The displacement of car after that time is 30.56 m.
Explanation:
Given that,
Initial velocity = 6.64 m/s
Acceleration = 0.85 m/s²
Time = 3.7 s
Final velocity = 9.8 m/s
We need to calculate the displacement
Using equation of motion
[tex]v^2=u^2+2as[/tex]
[tex]s=\dfrac{v^2-u^2}{2a}[/tex]
Put the value into the formula
[tex]s=\dfrac{9.8^2-6.64^2}{2\times0.85}[/tex]
[tex]s =30.56\ m[/tex]
Hence, The displacement of car after that time is 30.56 m.
