Respuesta :
Answer:
For diatomic oxygen:V=539.06 m/s
For carbon dia oxide:V=459.71 m/s
For dia atomic hydrogen:V=2156.25 m/s
Explanation:
As we know that
Root mean square velocity V
[tex]V=\sqrt{\dfrac{3RT}{M}}[/tex]
Where
R is the gas constant
[tex]R=8.31\ \frac{kg.m^2}{s^2.mol.K}[/tex]
T is the temperature (K).
M is the molecular weight.
For diatomic oxygen:
M=32 g/mol
T=273+100 = 373 K
[tex]R=8.31\ \frac{kg.m^2}{s^2.mol.K}[/tex]
[tex]V=\sqrt{\dfrac{3RT}{M}}[/tex]
[tex]V=\sqrt{\dfrac{3\times 8.31\times 373}{32\times 10^{-3}}}[/tex]
V=539.06 m/s
For carbon dia oxide
M=44 g/mol
T=273+100 = 373 K
[tex]R=8.31\ \frac{kg.m^2}{s^2.mol.K}[/tex]
[tex]V=\sqrt{\dfrac{3RT}{M}}[/tex]
[tex]V=\sqrt{\dfrac{3\times 8.31\times 373}{44\times 10^{-3}}}[/tex]
V=459.71 m/s
For dia atomic hydrogen:
M= 2 g/mol
T=273+100 = 373 K
[tex]R=8.31\ \frac{kg.m^2}{s^2.mol.K}[/tex]
[tex]V=\sqrt{\dfrac{3RT}{M}}[/tex]
[tex]V=\sqrt{\dfrac{3\times 8.31\times 373}{2\times 10^{-3}}}[/tex]
V=2156.25 m/s
