Answer: The mass of magnesium sulfate heptahydrate required is 2.46 g
Explanation:
To calculate the mass of solute for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Molarity of solution = 0.05 mol/L
Molar mass of magnesium sulfate heptahydrate = 246.47 g/mol
Volume of solution = 200 mL
Putting values in above equation, we get:
[tex]0.05mol/L=\frac{\text{Mass of }MgSO_4.7H_2O\times 1000}{246.47g/mol\times 200mL}\\\\\text{Mass of }MgSO_4.7H_2O=2.46g[/tex]
Hence, the mass of magnesium sulfate heptahydrate required is 2.46 g
