Answer:
for -12db
[tex]\frac{V1}{V2}=0.251\\\\\frac{P1}{P2}=0.0631[/tex]
for 3db
[tex]\frac{V1}{V2}=\sqrt{2}\\\\\frac{P1}{P2}=2[/tex]
for 10db
[tex]\frac{V1}{V2}=3.16\\\\\frac{P1}{P2}=10[/tex]
for 0db
[tex]\frac{V1}{V2}=1\\\\\frac{P1}{P2}=1[/tex]
Explanation:
The decibel is a logaritmic value given by:
[tex]db=10*log(\frac{P1}{P2})=20*log(\frac{V1}{V2})[/tex]
we use 10 for power values and 20 for other values such voltages or currents.
[tex]\frac{V1}{V2}=10^{\frac{db}{10}}\\\\\frac{P1}{P2}=10^{\frac{db}{20}}[/tex]
for -12db
[tex]\frac{V1}{V2}=10^{\frac{-12}{10}}=0.251\\\\\frac{P1}{P2}=10^{\frac{-12}{20}}=0.0631[/tex]
for 3db
[tex]\frac{V1}{V2}=10^{\frac{3}{10}}=\sqrt{2}\\\\\frac{P1}{P2}=10^{\frac{3}{20}}=2[/tex]
for 10db
[tex]\frac{V1}{V2}=10^{\frac{10}{10}}=3.16\\\\\frac{P1}{P2}=10^{\frac{10}{20}}=10[/tex]
for 0db
[tex]\frac{V1}{V2}=1\\\\\frac{P1}{P2}=1[/tex]
