Answer:
distance between the charges is 5.12 × 10⁶ m
Explanation:
charges q₁ = -130.0 C
q₂ = 180 C
force between the charges = 8 N
force between two charge
[tex]F = \dfrac{k q_1q_2}{r^2}[/tex]
value of K =8.975 × 10⁹ N.m²/C²
[tex]8 = \dfrac{8.975 \times 10^{9}\times 130 \times 180}{r^2}[/tex]
[tex]r^2 = \dfrac{8.975 \times 10^{9}\times 130 \times 180}{8}[/tex]
[tex]r^2 =2.625 \times 10^{13} [/tex]
r = 5.12 × 10⁶ m
hence, distance between the charges is 5.12 × 10⁶ m.
