Answer:
11.78 hours.
Step-by-step explanation:
We are asked to find the time that an "H" cylinder will last having 1350 PSI of gas in it at a flow of 6 LPM.
[tex]\text{Duration of tank (in minutes)}=\frac{\text{Tank pressure (in PSI)}\times\text{Conversion factor}}{\text{Flow (LPM)}}[/tex]
[tex]\text{Duration of H tank (in minutes)}=\frac{1350\times 3.14}{6}[/tex]
[tex]\text{Duration of H tank (in minutes)}=\frac{4239}{6}[/tex]
[tex]\text{Duration of H tank (in minutes)}=706.5[/tex]
To convert the time in hours, we will divide 706.5 by 60 as i hour equals 60 minutes.
[tex]\text{Duration of H tank (in hours)}=\frac{706.5}{60}[/tex]
[tex]\text{Duration of H tank (in hours)}=11.775[/tex]
Therefore, it will take 11.78 hours to last the given cylinder.
