Answer:
You need 0.8 ml of 5M stock solution and you have to add 9.2 ml of water.
Explanation:
Protocol solution (1X): 100 mM=0.1M
4X: 0.4M
The concentration of a solution is inversely proportional to the volume of a solution, so:
[tex]M_{1}V_{1}=M_{2}V_{2}[/tex]
where:
M1= 5M stock solution
V1= amount of solution we need to collect
M2=4X solution
V2= 10 ml (volumen of 4X solution)
Therefore:
5M×V1=0.4M×10ml
V1={0.4M}{5M}10ml=0.8ml
[tex]5M*V_{1}=0.4M*10ml\\ V_{1}=\frac{0.4M}{5M}10ml=0.8ml[/tex]
To make a 10 ml solution we have to add 9.2 ml of water because V2 es 10 ml.
