Answer: [tex](1,T), (2,T), (3,T), (4, T), (5,T), (6,T)\\(1,H), (2,H), (3,H), (4, H), (5,H), (6,H)[/tex]
Step-by-step explanation:
The total outcomes on a die = {1,2,3,4,5,6}=6
The total outcomes on a coin = {Tails or Heads}=2
The number of possible outcomes =[tex]6\times2=12[/tex]
If you roll one die and flip one coin, then the possible outcomes are:
[tex](1,T), (2,T), (3,T), (4, T), (5,T), (6,T)\\(1,H), (2,H), (3,H), (4, H), (5,H), (6,H)[/tex]
Here T denotes for Tails and H denotes for heads.
