Answer:
Step-by-step explanation:
Given that Z the set of integers is the universal set and
A is given in set builder form.
[tex]A = {x | x^2 ≤ 5}[/tex]
To convert this into roster form, we can find solutions for x
When [tex]x^2\leq 5\\|x|\leq \sqrt{5} =2.236[/tex]
i.e. all integers lying between -2.236 and 2.236
The only integers satisfying this conditions are
-2,-1,0,1,2
Hence A in roster form is
A=[tex]{-2,-1,0,1,2}[/tex]
