Respuesta :
Answer:
a.
silver iodide BC
manganese(II) hydroxide A
b.
silver iodide Ksp = S²
manganese(II) hydroxide Ksp = 4S³
Explanation:
Ksp (Solubility products) are the equilibrium constants for poorly soluble compounds. As every equilibrium constant, it is formed by the product of the products raised to their stoichiometric coefficients divided by the product of reactants raised to their stoichiometric coefficients. We only include in the constant gases and aqueous species. So, to solve this task, we need to write each reaction and its Ksp.
1. Silver Iodide
AgI(s) ⇄ Ag⁺(aq) + I⁻(aq)
When AgI is put in water, the concentration of Ag⁺ and I⁻ that actually dissolve is known as solubility (S). So the concentration of both Ag⁺ and I⁻ would be S.
AgI(s) ⇄ Ag⁺(aq) + I⁻(aq)
S S
We can replace this in the Ksp expression:
Ksp = [Ag⁺].[I⁻] = S.S = S²
We can follow the same steps to find out the relationship between Ksp and S for each compound.
2. Mn(OH)₂(s) ⇄ Mn²⁺(aq) + 2OH⁻(aq)
S 2S
In this case, the concentration of OH⁻ is 2S because 2 moles are produced along with 1 mole of Mn²⁺.
Ksp = [Mn²⁺].[OH⁻]² = S.(2S)² = 4S³
A. Fe(OH)₂(s) ⇄ Fe²⁺(aq) + 2OH⁻(aq)
S 2S
Ksp = [Fe²⁺].[OH⁻]² = S.(2S)² = 4S³
B. CaSO₃(s) ⇄ Ca²⁺(aq) + SO₃²⁻(aq)
S S
Ksp = [Ca²⁺].[SO₃²⁻] = S.S = S²
C. NiCO₃(s) ⇄ Ni²⁺(aq) + CO₃²⁻(aq)
S S
Ksp = [Ni²⁺].[CO₃²⁻] = S.S = S²
D. Ba₃(PO₄)₂(s) ⇄ 3 Ba²⁺(aq) + 2 PO₄³⁻(aq)
3S 2S
Ksp = [Ba²⁺]³.[PO₄³⁻]²= (3S)³.(2S)²= 108S⁵
a. The salts that can be compared using the same Ksp expressions are:
silver iodide BC
manganese(II) hydroxide A
b.
silver iodide Ksp = S²
manganese(II) hydroxide Ksp = 4S³