Answer:Momentum of Truck[tex]=4000\times 20=80,000 kg-m/s[/tex]
Momentum of car[tex]=1350\times 10=13,500 kg-m/s[/tex]
Explanation:
Given
mass of truck(m)=4000 kg
Velocity of Truck is ([tex]V_T[/tex])=[tex]-20\hat{j}[/tex]
mass of car ([tex]m_c[/tex])=1350 kg
Velocity of car[tex](V_c)=10 \hat{j}[/tex]
Conserving momentum
[tex]4000\times \left ( -20\right )+1350\left ( 10\right )=5350v[/tex]
[tex]v=\frac{66,500}{5350}=12.42 m/s[/tex]
Momentum of Truck[tex]=4000\times 20=80,000 kg-m/s[/tex]
Momentum of car[tex]=1350\times 10=13,500 kg-m/s[/tex]
Answer:
1) Momentum of truck before collision is [tex]\overrightarrow{p_{1}}=-80000kgm/s[/tex]
2) Momentum of car before collision is [tex]\overrightarrow{p_{2}}=13500kgm/s[/tex]
Explanation:
The momentum of an object with mass 'm' travelling with speed 'v' is mathematically given by
[tex]\overrightarrow{p}=mass\times \overrightarrow{v}[/tex]
In this problem we shall assume that direction's coincide with the Cartesian axis for simplicity
Thus for Truck we have
Mass = 4000 kg
Velocity = [tex]-20\widehat{j}[/tex]m/s
Thus momentum of truck becomes
[tex]\overrightarrow{p_{1}}=4000\times -20\overrightarrow{j}=-80000kgm/s[/tex]
Similarly for car we have
Mass = 1350 kg
Velocity = [tex]10\widehat{j}[/tex]m/s
Thus momentum of car becomes
[tex]\overrightarrow{p_{2}}=1350\times 10\overrightarrow{j}=13500kgm/s[/tex]
