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You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up. The ruler has −14 µC of charge. The tissue has 5 g of mass. What is the minimum charge required to pick up the tissue paper?

Respuesta :

Answer:

q=1.4*10^{-9}C

Explanation:

Given data:

charge on ruler = -14μC

Mass of tissue is 5 g

To Know the minimum charge,  equate electrostatic force to weight  

we have F = W

so[tex]\frac{KQq}{r^2} =mg[/tex]

putting all value in equation,

[tex]=\frac{9*10^9*(14*10^{-6})*q}{0.06^2} = 5* 10^{-3}*9.8[/tex]

solving for q

[tex]q =\frac{5* 10^{-3}*9.8 *0.06^2}{9*10^9*(14*10^{-6})}[/tex]

or q=1.4*10^{-9}C

okpalawalter8

We have that for the Question "What is the minimum charge required to pick up the tissue paper?" it can be said that minimum charge is

  • q=0.0014\muC

From the question we are told

  • You hold a ruler that has a charge on its tip 6 cm above a small piece of tissue paper to see if it can be picked up.
  • The ruler has −14 µC of charge. The tissue has 5 g of mass.
  • What is the minimum charge required to pick up the tissue paper?

minimum charge

Generally the equation for the Electro static force  is mathematically given as

[tex]\frac{kqq'}{r^2}=mg\\\\Therefore\\\\q=\frac{5*10^{-3}*9.8*(0.06^)^2}{9*10^{9}*14*10^{-6}}\\\\q=1.4*10^{-9}C\\\\q=1.4mc\\\\[/tex]

q=0.0014\muC

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