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Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial acceleration (in m/s2) of this massif it is released and allowed to move?

Respuesta :

Answer:

acceleration = 0.8181 m/s²

Explanation:

given data

mass = 1.1 kg

apart d = 1 m

charge q = 10 μC

to find out

What is the initial acceleration

solution

we know that acceleration is

acceleration = [tex]\frac{force}{mass}[/tex]   .................1

here force = [tex]k \frac{q1q2}{r^2}[/tex]

here q1 q2 is charge and r is distance and Coulomb constant k = 9 × [tex]10^{9}[/tex] Nm²/C²

force = [tex]9*10^{9} \frac{(10*10^{-6})^2}{1^2}[/tex]

force = 0.9 N

so  from equation 1

acceleration = [tex]\frac{0.9}{1.1}[/tex]

acceleration = 0.8181 m/s²

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