Respuesta :
Answer:
The shift in the color's depends on the angle of incidence, for a special case when the angle of incidence is along the normal to the surface no shift will be observed.
Explanation:
When a ray of light is incident on a medium perpendicular to it it does not undergo any refraction thus no shift will be seen.
Answer:
The distance between the emergent red and blue light is 3 cm
Solution:
As per the question:
Thickness of the glass plate, s = 10 cm = 0.1 m
Refractive index of blue light, [tex]n_{blue} = 1.6[/tex]
Refractive index of blue light, [tex]n_{red} = 1.3[/tex]
Now, to calculate the distance between red and blue light as it emerges from the plate:
We know that refractive index is given as the ratio of speed of light in vacuum, c or air to that in medium, [tex]v_{m}[/tex].
[tex]n = \frac{c}{v_{m}}[/tex]
[tex]v_{m} = \frac{c}{n}[/tex] (1)
Since, c is constant, thus
n ∝ [tex]\frac{1}{v_{m}}[/tex]
Now, the refractive index of blue light is more than that of red light thus its speed in medium is lesser than red light.
Now, time taken, t by red and blue light to emerge out of the glass slab:
[tex]s = v_{m}\times t[/tex]
[tex]t = \frac{s}{v_{blue}} = \frac{sn_{blue}}{c}[/tex]
In the same time, red light also traveled through the glass covering some distance in air say x
[tex]t' = \frac{s}{v_{red}} = \frac{sn_{red}}{c}[/tex] (2)
Time taken by red light to cover 'x' distance in vacuum is t'':
[tex]t" = \frac{x}{c}[/tex]
Now,
t = t' + t" (3)
From eqn (1), (2) and (3):
[tex]\frac{sn_{blue}}{c} = \frac{sn_{red}}{c} + \frac{x}{c}[/tex]
Now, putting appropriate values in the above eqn:
[tex]\frac{0.1\times 1.6}{c} = \frac{0.1\times 1.3}{c} + \frac{x}{c}[/tex]
[tex]\frac{0.16}{c} - \frac{0.13}{c} = \frac{x}{c}[/tex]
x = 0.03 m = 3 cm
