Answer:
4.51 * 10^{-5} C
Explanation:
The force between two charge q and q1 is given as
[tex]F = \frac{k*q*q1}{r^2}[/tex]
[tex]= \frac{(9.0 * 10^9)(24 * 10^{-6})(8 * 10^{-6} C)}{(0.19m)^2} [/tex]
= 47.86 N in the +y direction
We need the force between q and q2 to be (47.86 - 18) = 29.86 N in the other direction to get the desired result.
solving for q2,
[tex]q2 = \frac{Fr^2}{(kq)} [/tex]
[tex]= \frac{(29.86)(0.33 m)^2}{(9.0 * 10^9*8*10^{-6} C)}[/tex]
[tex]= 4.51 * 10^{-5} C[/tex]
