Answer:
Acceleration of the car, [tex]a=8\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of the car, u = 0 (at rest)
Final speed of the car, v = 40 m/s
Distance covered, s = 100 m
We need to find the acceleration of the car. It can be calculated using third equation of motion as :
[tex]v^2-u^2=2as[/tex]
a is the acceleration of the car
[tex]a=\dfrac{v^2}{2s}[/tex]
[tex]a=\dfrac{(40)^2}{2\times 100}[/tex]
[tex]a=8\ m/s^2[/tex]
So, the acceleration of the car is [tex]8\ m/s^2[/tex]. Hence, this is the required solution
