Answer:
r = 5.335 meters
Explanation:
Given that,
Charge 1, [tex]q_1=-165\ \mu C[/tex]
Charge 2, [tex]q_2=115\ \mu C[/tex]
Force of attraction between two charges, F = 6 N
The force of attraction between two charges is given by :
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex], r is the separation between two charges
[tex]r=\sqrt{\dfrac{kq_1q_2}{F}}[/tex]
[tex]r=\sqrt{\dfrac{9\times 10^9\times 165\times 10^{-6}\times 115\times 10^{-6}}{6}}[/tex]
r = 5.335 m
So, the separation between two charges is 5.335 meters. Hence, this is the required solution.
