Respuesta :
Answer:
For a: The isotopic representation of iodine is [tex]_{53}^{131}\textrm{I}[/tex]
For b: The isotopic representation of cesium is [tex]_{55}^{137}\textrm{Cs}[/tex]
For c: The isotopic representation of strontium is [tex]_{38}^{52}\textrm{Sr}[/tex]
Explanation:
The isotopic representation of an atom is: [tex]_Z^A\textrm{X}[/tex]
where,
Z = Atomic number of the atom
A = Mass number of the atom
X = Symbol of the atom
- For a:
We are given:
Number of neutrons = 78
Atomic number of iodine = 53 = Number of protons
Mass number = 53 + 78 = 131
Thus, the isotopic representation of iodine is [tex]_{53}^{131}\textrm{I}[/tex]
- For b:
We are given:
Number of neutrons = 82
Atomic number of cesium = 55 = Number of protons
Mass number = 55 + 82 = 137
Thus, the isotopic representation of cesium is [tex]_{55}^{137}\textrm{Cs}[/tex]
- For c:
We are given:
Number of neutrons = 52
Atomic number of strontium = 38 = Number of protons
Mass number = 38 + 52 = 90
Thus, the isotopic representation of strontium is [tex]_{38}^{52}\textrm{Sr}[/tex]
