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A 0.50 Kg billard ball moving at 1.5 m/s strikes a second 0.50 kg billiard ball which is at rest on the table.If the first ball slows down to a speed of 0.10 m/s, then what is the speed of the second ball ? Please explain.

Respuesta :

Answer:

velocity of second billiard after collision = 1.4 m/sec  

Explanation:

We have mass of billiard let [tex]m_1=0.5kg[/tex]

Velocity of billiard let [tex]v_1=1.5m/sec[/tex]

Mass of second second billiard let [tex]m_2=0.5kg[/tex]

Velocity of second billiard before collision 0 m/sec  billiard

Velocity of first billiard after collision  0.1 m/sec

Now according conservation of momentum

Momentum before collision and after collision will be same

So momentum before collision = momentum after collision

[tex]0.5\times 1.5+0.5\times 0=0.5\times 0.1+0.5\times velovity\ of\ second\ biliard\ after\ collision[/tex]

So velocity of second billiard after collision = 1.4 m/sec  

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