Answer:
W = 289.70 kg
Explanation:
Given data:
Pressure in tank = 23 atm
Altitude 1000 ft
Air temperature in tank T = 700 F
Volume of tank = 800 ft^3 = 22.654 m^3
from ideal gas equation we have
PV =n RT
Therefore number of mole inside the tank is
[tex]\frac{1}{n} = \frac{RT}{PV}[/tex]
[tex] = \frac{8.206\times 10^{-5}} 644.261}{23\times 22.654}[/tex]
[tex]= 1.02\times 10^{-4}[/tex]
[tex]n = 10^4 mole[/tex]
we know that 1 mole of air weight is 28.97 g
therefore, tank air weight is [tex]W = 10^4\times 28.91 g = 289700 g[/tex]
W = 289.70 kg
