Answer:
18.86° , it will bend towards normal.
Explanation:
For refraction,
Using Snell's law as:
[tex]n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}[/tex]
Where,
[tex]{\theta_i}[/tex] is the angle of incidence ( 25.0° )
[tex]{\theta_r}[/tex] is the angle of refraction ( ? )
[tex]{n_r}[/tex] is the refractive index of the refraction medium (n=1.7)
[tex]{n_i}[/tex] is the refractive index of the incidence medium ( n=1.3)
Hence,
[tex]1.3\times {sin\ 25.0^0}={1.7}\times{sin\theta_r}[/tex]
Angle of refraction = [tex]sin^{-1}0.3232[/tex] = 18.86°
Since, the light ray is travelling from a material with a refractive index of 1.3 into a material with a refractive index of 1.7 or lighter to denser medium, it will bend towards normal.
The diagram is shown below:
