Respuesta :
Answer:
G1=36,G2=12,G3=4,G4=4/3,G5=4/9
Step-by-step explanation:
Since the nth term is given by;
Gn= 36(1/3)^n-1, then, substitute the values of n as 1,2,3,4 and 5 to get the values of G1,G2,G3,G4 and G5 respectively.
G1=36(1/3)^1-1 = 36
G2= 36(1/3)^2-1= 12
G3= 36(1/3)^3-1 = 4
G4= 36(1/3)^4-1 = 4/3
G5= 36(1/3)^5-1=4/9
Answer:
36, 12, 4, 4/3, 4/9.
Step-by-step explanation:
We find each term by substituting the sequence number.
So the first term (where n = 1)
= 36(1/3)^(1-1)
= 36(1/3)^0
= 36 * 1
= 36.
The second term is 36(1/3)^(2-1) = 36 * 1/3
= 12.
We can find subsequent terms by just multiplying the previous term by 1/3 so the third term = 12 * 1/3 = 4.
So the first 5 terms are 36, 12, 4, 4/3, 4/9.
