In a LOS communication, consider d = 60km, the requirement is to make two antennas (transmitter and receiver) such that the height of one antenna should be four time of the other. Considering this, find the appropriate heights of these two antennas.

Respuesta :

Answer:

for ratio 1:4

height for antenna 1 = 42.36

and height for antenna 2 =169.46

Explanation:

given data

distance d = 60km

height h1 = 4 h2

to find out

find the appropriate heights of these two antennas

solution

we know here that distance between 2 antennas  in LOS ( line of sight ) is express as

[tex]d = 3.57\sqrt{kh}[/tex]   ......................1

here d is distance and k is curvature of earth i.e 4/3  and h is height

we know height is 1:4 so total height is 5 part to get ratio

put value in equation 1

[tex]60 = 3.57\sqrt{\frac{4}{3} h}[/tex]  

solve it we get

h = 211.83

so for ration divide by 5

[tex]\frac{211.83}{5}[/tex]

= 42.36

so for ratio 1:4

so height for antenna 1 = 42.36

and height for antenna 2 = 4 × 42.36 = 169.46