Answer: [tex]0.1851 \frac{kg}{m^{3}}[/tex]
Explanation:
We have this concentration in units of [tex]mg/ml[/tex]:
[tex]\frac{45 mg}{243 ml}[/tex]
And we need to express it in [tex]kg/m^{3}[/tex], knowing:
[tex]1 ml= 1 cm^{3}[/tex]
[tex]1 m^{3}= (100 cm) ^{3}[/tex]
[tex]1g = 1000 mg[/tex]
[tex]1 kg = 1000 g[/tex]
Hence:
[tex]\frac{45 mg}{243 cm^{3}} \frac{1 g}{1000 mg} \frac{1 kg}{1000 g} \frac{(100 cm) ^{3}}{1 m^{3}}=0.1851 \frac{kg}{m^{3}}[/tex]
